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fluturel
Joined: 13 Jul 2010
Posts: 13
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 Posted: Wed Jul 14, 2010 11:04 pm Post subject: Simple XML parser |
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I have an XML file just like the following:
| Code: | <?xml version="1.0" encoding="UTF-8"?>
<Personnel>
<Employee type="permanent">
<Name>Seagull</Name>
<Id>3674</Id>
<Age>34</Age>
</Employee>
<Employee type="contract">
<Name>Robin</Name>
<Id>3675</Id>
<Age>25</Age>
</Employee>
<Employee type="permanent">
<Name>Crow</Name>
<Id>3676</Id>
<Age>28</Age>
</Employee>
</Personnel>
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So nothing too complex. Just the basics. What's the easiest way of parsing this kind of XMLs ? Something like this would be nice:
| Code: | String xmlAsAString;
XML xml = XML.parse(xmlAsAString);
System.out.println(xml.Employee[0].name); |
Being so many parsers i really don't know which one to use  |
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proximityinfotech6
Joined: 13 Jul 2010
Posts: 2
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| Posted: Thu Jul 15, 2010 5:03 am Post subject: |
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This is where it gets complicated - because I'm on a client's server and he's running nginx (essentially apache rewritten by some crazy Russian to be lean so I'm told) which I've never used before. So - I don't know exactly if these packages are needed here as a result of the upgrade to 2.4? It seems unlikely as this would be detailed in the upgrade docs. SS 2.3.6 runs beautifully on this server, s
I'm all sorts of confused, but leaning toward nginx not being the issue here.
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Shagil t
Posted via mailing list.
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| Posted: Fri Jul 16, 2010 6:07 pm Post subject: Re: Simple XML parser |
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I think JAXB will be a good choice.
http://java.sun.com/developer/technicalArticles/WebServices/jaxb/
On Thu, Jul 15, 2010 at 4:35 AM, fluturel <address-removed ([email]address-removed[/email])> wrote:
| Quote: | I have an XML file just like the following:
Code:
<?xml version="1.0" encoding="UTF-8"?>
<Personnel>
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nestor gomez munoz
Posted via mailing list.
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| Posted: Fri Jul 16, 2010 7:35 pm Post subject: Re: Simple XML parser |
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If JAXB is not a choise, you can use the java XPahtAPI , and program
something like
String xpathExpression = "/Personnel/Employee";
Node nodes = (Node) xpath.evaluate(xpathExpression,
inputSource, XPathConstants.NODE);
for (int j = 0; j < nodes.getLength(); j++) {
xpathExpression = "./@type";
eType = (String) xpath.evaluate(xpathExpression,
nodes.item(j),
XPathConstants.STRING);
eName = xpath.evaluate("./Name", nodes.item(j),
XPathConstants.STRING);
eId = xpath.evaluate("./Id",nodes.item(j),
XPathConstants.INTEGER);
eAge = xpath.evaluate("./Age",nodes.item(j),
XPathConstants.INTEGER);
}
El vie, 16-07-2010 a las 23:12 +0530, Shagil t escribió:
| Quote: | I think JAXB will be a good choice.
http://java.sun.com/developer/technicalArticles/WebServices/jaxb/
On Thu, Jul 15, 2010 at 4:35 AM, fluturel <address-removed> wrote:
I have an XML file just like the following:
Code:
<?xml version="1.0" encoding="UTF-8"?>
<Personnel>
<Employee type="permanent">
<Name>Seagull</Name>
<Id>3674</Id>
<Age>34</Age>
</Employee>
<Employee type="contract">
<Name>Robin</Name>
<Id>3675</Id>
<Age>25</Age>
</Employee>
<Employee type="permanent">
<Name>Crow</Name>
<Id>3676</Id>
<Age>28</Age>
</Employee>
</Personnel>
So nothing too complex. Just the basics. What's the easiest
way of parsing this kind of XMLs ? Something like this would
be nice:
Code:
String xmlAsAString;
XML xml = XML.parse(xmlAsAString);
System.out.println(xml.Employee[0].name);
Being so many parsers i really don't know which one to use :?
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